The area of a square field is 60025m2. A man cycles along its boundary

1.	The area of a square field is 60025m2. A man cycles along its boundary at 18 Km/hr. In how much time will he return at the starting point?
Answer» Area of square field = 60025 m² Speed of cyclist = 18 km/h = 18 x \(\frac{1000}{60X60}\) = 5 m/s² Area = 60025 m² Side² = 60025 Side = \(\sqrt{60025}\) = 245 Therefore, Total length of boundary = 4 × Side = 4 × 245 = 980 m Hence, Time taken = \(\frac{980}{5}\) = 196 seconds = 3 minutes and 16 seconds

The area of a square field is 60025m2. A man cycles along its boundary at 18 Km/hr. In how much time will he return at the starting point?

Answer»

Area of square field = 60025 m²

Speed of cyclist = 18 km/h

= 18 x \(\frac{1000}{60X60}\)

= 5 m/s²

Area = 60025 m²

Side² = 60025

Side = \(\sqrt{60025}\)

= 245

Therefore,

Total length of boundary = 4 × Side

= 4 × 245

= 980 m

Hence, Time taken = \(\frac{980}{5}\)

= 196 seconds

= 3 minutes and 16 seconds