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The area of each plate of parallel plate condenser is `20cm^(2)` and distance them is 2mm. It stores the energy if 5J. The energy density of electric field between its plates isA. `250xx10^(6)J//m^(3)`B. `1.25xx10^(6)J//m^(3)`C. `2xx10^(6)J//m^(3)`D. `4xx10^(6)J//m^(3)` |
Answer» Correct Answer - B `A=20Cm^(2),d=2mm,U=5J,u=?` `u=("energy")/("volume")=U/(A.d)=5/(20xx10^(-4)xx2xx10^(-3))` `=1.25xx10^(6)J//m^(3)` |
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