1.

The area of one end of a U-tube is 0.01 m2 and that of the other end the force 1 m2, When a force was applied on the liquid at the first end?

Answer»

A1 = 0.01 m2

A2 = 1 m2

F1 = ?

F2 = 20000 N

\(\frac{F_1}{F_2}=\frac{A_1}{A_2}\)

\(F_1=F_2\times\frac{A_1}{A_2}=20000\times\frac{0.01}{1}=200\,N\)



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