1.

The area of the parallelogram ABCD is 1470 sq. cm. If AB = 49 cm and AD = 35 cm then, find the height, DF and BE.

Answer»

Area of the parallelogram = 1470 sq. cm 

Considering AB = base = 49 cm

Height = DF 

Area = base x height 

49 x DF = 1470 

DF = \(\frac{1470}{49}\)

DF = 30 cm 

Now considering AD as base 

Base = AD = 35 cm; height = BE

Base x Height = 1470 

35 x BE = 1470 : BE = \(\frac{1470}{35}\)

BE = 42 cm; DF = 30 cm; BE = 42 cm



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