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The area of the parallelogram ABCD is 1470 sq. cm. If AB = 49 cm and AD = 35 cm then, find the height, DF and BE. |
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Answer» Area of the parallelogram = 1470 sq. cm Considering AB = base = 49 cm Height = DF Area = base x height 49 x DF = 1470 DF = \(\frac{1470}{49}\) DF = 30 cm Now considering AD as base Base = AD = 35 cm; height = BE Base x Height = 1470 35 x BE = 1470 : BE = \(\frac{1470}{35}\) BE = 42 cm; DF = 30 cm; BE = 42 cm |
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