The area of the plates of a parallel plate condenser is `A` and the distance between the plates is `10 mm`. There are two dielectric sheets in it, one of dieectirc constant `10` and thickness `6 mm` an dthe other of dielectric constant `5` and thickness `4 mm`. the capacity of the condenser isA. `5000/7in_(0)A`B. `500/7in_(0)A`C. `50/7in_(0)A`D. `50/14in_(0)A`

The area of the plates of a parallel plate condenser is `A` and the di

1.	The area of the plates of a parallel plate condenser is `A` and the distance between the plates is `10 mm`. There are two dielectric sheets in it, one of dieectirc constant `10` and thickness `6 mm` an dthe other of dielectric constant `5` and thickness `4 mm`. the capacity of the condenser isA. `5000/7in_(0)A`B. `500/7in_(0)A`C. `50/7in_(0)A`D. `50/14in_(0)A`
Answer» Correct Answer - A `C=(in_(0)A)/(t_(1)/K_(1)+t_(2)/K_(2))=(in_(0)A)/((6xx10^(-3))/10+(4xx10^(-3))/5)` `C=5000/7in_(0)A`

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