The areas of three consecutive faces of a cuboid are 9 cm2, 25 cm2 and

1.	The areas of three consecutive faces of a cuboid are 9 cm2, 25 cm2 and 36 cm2, then the volume (in cm2) of 1. 602. 903. 30004. 100
Answer» Correct Answer - Option 2 : 90 Given: Areas of three consecutive faces of a cuboid = 9 cm², 25 cm² and 36 cm² Formula used: Volume = √Area₁ × √Area₂ × √Area₃ Calculation: Volume = √9 × √25 × √36 cm² ⇒ 3 × 5 × 6 cm² ⇒ 90 cm² ∴ The required volume of cuboid is 90 cm²

The areas of three consecutive faces of a cuboid are 9 cm2, 25 cm2 and 36 cm2, then the volume (in cm2) of 1. 602. 903. 30004. 100

Answer» Correct Answer - Option 2 : 90

Given:

Areas of three consecutive faces of a cuboid = 9 cm², 25 cm² and 36 cm²

Formula used:

Volume = √Area₁ × √Area₂ × √Area₃

Calculation:

Volume = √9 × √25 × √36 cm²

⇒ 3 × 5 × 6 cm²

⇒ 90 cm²

∴ The required volume of cuboid is 90 cm²

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The areas of three consecutive faces of a cuboid are 9 cm2, 25 cm2 and 36 cm2, then the volume (in cm2) of 1. 602. 903. 30004. 100

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