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The argument of the complex number ` sin 6pi/5 + i ( 1 + cos 6pi/5)` is |
Answer» `2sin3/5picos3/5pi+i(1+2cos^23/5pi-1)` `2cos3/5pi[sin3/5pi+icos3/5pi]` `2cos3/5pi[sin(pi/2+pi/10)+icos(pi/2+pi/10)]` `2cos3/5pi[cospi/10+isin(-pi/10)]` `2cos3/5pi[cos(-pi/10)+isin(-pi/10)]` `-2sinpi/10[cos(-pi/10)+isin(-pi/10)]` `2sinpi/10[cos(9/10pi)+isin(9/10pi)]` option 3 is correect. |
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