1.

The arithmetic mean of the ordinates of the feet of the normals from (2,6) to the parabola `y^2=4x` is

Answer» `(at^2, 2at) = (t^2,2t)`
N`=> y= -tx + 2at + at^3`
`y = -tx + 2t + t^3`-(2,6)
`6 = -2t + 2t + t^3`
`t^3 = 6`
`t^3- 6=0`
lets say , `t_1 + t_2 + t_3 = 0`
mean =`(2at_1 + 2 at_2+ 2at_3)/2`
`=0`
Answer


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