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The arithmetic mean of the ordinates of the feet of the normals from (2,6) to the parabola `y^2=4x` is |
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Answer» `(at^2, 2at) = (t^2,2t)` N`=> y= -tx + 2at + at^3` `y = -tx + 2t + t^3`-(2,6) `6 = -2t + 2t + t^3` `t^3 = 6` `t^3- 6=0` lets say , `t_1 + t_2 + t_3 = 0` mean =`(2at_1 + 2 at_2+ 2at_3)/2` `=0` Answer |
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