1.

The arrangement of X^(-)ions around A^(-)ion is solid AX is given in the fig (not drawn to scale) If the radius of X^(-) is 250 pm, the radius of A^(+)is

Answer»

104 pm
125 pm
183 pm
57 pm

Solution :Cation`A^(+)`OCCUPIES octahedral VOID FORMED by anion `X^(-)`
RADIUS of octahedral void = `0.414times"Radius of the anion packing"`
=`0.414times250 "pm"`
=`103.5 "pm"cong104 "pm"`


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