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The arrangement of `X^(ɵ)` ions around `A^(o+)` ion in solid `AX` is given in the figure (not drawn to scale). If the radius of `X^(ɵ)` is `250 pm`, the radius of `A^(o+)` is A. 104pmB. 125pmC. 183pmD. 57pm |
Answer» Correct Answer - A The given arrangement is octahedral void arrangement. `rarr (r_(A)^(+))/(r_(X^(-)))ge0.414rArrr_(A)^(+)ge0.414xx250` `r_(A)^(+)ge103.5`pm `& (r_(A)^(+))/(r_(A)^(-))lt0.732rArrr_(A)^(+)lt183`pm |
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