The arrangement of `X^(ɵ)` ions around `A^(o+)` ion in solid `AX` is given in the figure (not drawn to scale). If the radius of `X^(ɵ)` is `250 pm`, the radius of `A^(o+)` is A. 104 pmB. 125 pmC. 183 pmD. 57 pm

The arrangement of `X^(ɵ)` ions around `A^(o+)` ion in solid `AX` is

1.	The arrangement of `X^(ɵ)` ions around `A^(o+)` ion in solid `AX` is given in the figure (not drawn to scale). If the radius of `X^(ɵ)` is `250 pm`, the radius of `A^(o+)` is A. 104 pmB. 125 pmC. 183 pmD. 57 pm
Answer» Correct Answer - A For octahedral voids : `(r^(+))/(r_(-))=0.414-0.732` `r^(+)=0.414xxr^(-)=0.414xx250=10.3.5` pm or `r^(+)=0.732xx250=183` pm No, suitable information is given therefore 104 pm will be most suitable answer by considering the extact fit ion in the void.

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The arrangement of `X^(ɵ)` ions around `A^(o+)` ion in solid `AX` is given in the figure (not drawn to scale). If the radius of `X^(ɵ)` is `250 pm`, the radius of `A^(o+)` is A. 104 pmB. 125 pmC. 183 pmD. 57 pm

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