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The atmospheric pressure on a certain day is `732 mm Hg`. What is the pressure in `kPa`?A. `60 kPa`B. `80.6 kPa`C. `77.8 kPa`D. `97.6 kPa` |
Answer» Correct Answer - D The relation between atmospheres and pascals is 1 atm = 101325 Pa `= 1.01325 xx 10^(5) Pa` Since `1000 Pa = 1 Pa ("kilopascal")` 1 atm = `1.01325 xx 10^(2) kPa` Thus, the atmospheric pressure in `kPa` is Pressure = `(732 mm Hg) xx ((1 "atm")/(760 mm Hg))xx ((1.01325 xx 10^(2) kPa)/(1 "atm"))` ` = 97.6 kPa` |
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