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The atomic masses of 'He' and 'Ne' are 4 and 20 a.m.u respectively. The value of the de Broglie wavelength of 'He' gas at -73 .^(@)C is ''M'' times that of the de Broglie wavelength of 'Ne' at 727 .^(@)C. 'M' is |
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Answer» `:. (lamda_(He))/(lamda_(Ne)) = (m_(He) XX v_(He))/(m_(He) xx v_(He)) = (M_(Ne) xx v_(Ne))/(M_(He) xx v_(He))` As `V = sqrt((3RT)/(M)) , (v_(Ne))/(v_(He)) = sqrt((T_(Ne))/(M_(Ne)) xx (M_(He))/(T_(He)))` `:. (lamda_(He))/(lamda_(Ne)) = (M_(Ne))/(M_(He)) xx sqrt((T_(Ne))/(T_(He)) xx (M_(He))/(M_(Ne)))` `= sqrt((M_(Ne) T_(Ne))/(M_(He) T_(He))) = sqrt((20 xx 1000)/(4xx 200)) = 5` `:. lamda_(He) = 5 lamda_(Ne)` |
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