The atomic numbers of nitrogen, oxygen and fluorine are 7 , 8 and 9 respectively. Write the electronic configuration of each element and answer the following questions:(a) Which one of N, O and F is most electronegative and which one is least electronegative?(b) What is the number of valence electrons of F?(c) What is valency of each one of N, O and F?

The atomic numbers of nitrogen, oxygen and fluorine are 7 , 8 and 9 re

1.	The atomic numbers of nitrogen, oxygen and fluorine are 7 , 8 and 9 respectively. Write the electronic configuration of each element and answer the following questions:(a) Which one of N, O and F is most electronegative and which one is least electronegative?(b) What is the number of valence electrons of F?(c) What is valency of each one of N, O and F?
Answer» Electronic configuration of Nitrogen : 2,5 Oxygen: 2, 6 Fluorine: 2.7 (a) Fluorine (F) is most electronegative and nitrogen (N) is least electronegative. (b) Fluorine (F) has 7 valence electrons. (c) Valency of nitrogen is 3 and 5. valency of oxygen is 2, valency of fluorine is 1.