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The atomic weights of two elements (A and B) are 20 and 40 respectively. If x % of A contains y atoms, how many atoms are present in 2x g of B? |
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Answer» Solution :Number of MOLES of `A = X/20` Number of atoms of `A = x/20 xx N` (N is the Av. Const) `therefore y=x/20 xx N , x = (20y)/N` Further, number of moles of B`=(2x)/40 xx N` `=(2N)/40 xx (20 y)/N` =y |
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