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The atoms of element ‘Y’ form hexagonal close packing and the atoms of element X occupies \(\cfrac{2}{3}\)rd portion of the number of tetrahedral voids. Write the formula of the compound formed by X and Y.(A) X2Y2(B) X2Y(C) X3Y4(D) X4Y3 |
Answer» Correct answer is: (D) X4Y3 Let the number of atoms of element Y in hcp unit cell be n. \(\therefore\) Number of tetrahedral voids = 2n As 2/3rd of the tetrahedral voids are occupied by atoms of element X, Number of atoms of element X = 2n\(\times \cfrac{2}{3}=\cfrac{4n}{3}\) \(\therefore\) Ratio of atoms of element X : atoms of element Y =\(\cfrac{4n}{3}\):n = 4 : 3 The formula of the compound is X4Y3. |
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