The average age of A, B and C is 22. A’s age is 6 times that of B wh

1.	The average age of A, B and C is 22. A’s age is 6 times that of B which is 3 times that of C. What is A’s age?1). 542). 33). 64). 9
Answer» Trick: One thing is clear that A is elder than B and B is elder than C Now going through OPTIONS LET's assume A's age is 9 and according to the question STATEMENT B's age is 1.5 and C's would be 0.5 This is not possible as average would be less than 22 which contradicts the other statement Same will be valid for options 2 and 3 i.e. 3 and 6. Hence eliminating options 2, 3 and 4 Therefore correct option is 1 Alternative solution: Total of all the three ages = 22 ? 3 = 66 ⇒ A = 6B ⇒ A/B = 6....(1) ⇒ B = 3C ⇒ B/C = 3 Multiply both numerator and denominator of equation (1) by 3 ⇒ A/B = 18/3 ⇒ A : B : C = 18 : 3 : 1 ∴ A’s age = $(\FRAC{{18}}{{22}} \times 66)$ = 54 years

The average age of A, B and C is 22. A’s age is 6 times that of B which is 3 times that of C. What is A’s age?1). 542). 33). 64). 9

Answer»

Trick: One thing is clear that A is elder than B and B is elder than C

Now going through OPTIONS LET's assume A's age is 9 and according to the question STATEMENT B's age is 1.5 and C's would be 0.5

This is not possible as average would be less than 22 which contradicts the other statement

Same will be valid for options 2 and 3 i.e. 3 and 6.

Hence eliminating options 2, 3 and 4

Therefore correct option is 1

Alternative solution:

Total of all the three ages = 22 ? 3 = 66

⇒ A = 6B

⇒ A/B = 6....(1)

⇒ B = 3C

⇒ B/C = 3

Multiply both numerator and denominator of equation (1) by 3

⇒ A/B = 18/3

⇒ A : B : C = 18 : 3 : 1

∴ A’s age = $(\FRAC{{18}}{{22}} \times 66)$ = 54 years