1.

The average density and time period of a planet are rho and T. A satellite is revolving just above the surface of planet. If the universal gravitational constant is G, then T^(2) is equal to

Answer»

`(3pi)/(G RHO)`
`(4pi G)/(rho^(2))`
`(4pi^(2)G)/(pi rho)`
`(1)/(rho G pi)`

Solution :As `v_(0) = sqrt((GM)/(R ))`
`T = (2PI R)/(v_(0)) = (2pi R)/(sqrt((GM)/(R )))`
`= 2pi sqrt((R^(3))/(GM)) = 2pi sqrt((R^(3))/(G.(4)/(3)pi R^(3) rho))`
`T^(2) = 4pi^(2)(3)/(G xx 4 pi rho)`
`T^(2) = (3pi)/(G rho)`


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