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The average density and time period of a planet are rho and T. A satellite is revolving just above the surface of planet. If the universal gravitational constant is G, then T^(2) is equal to |
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Answer» `(3pi)/(G RHO)` `T = (2PI R)/(v_(0)) = (2pi R)/(sqrt((GM)/(R )))` `= 2pi sqrt((R^(3))/(GM)) = 2pi sqrt((R^(3))/(G.(4)/(3)pi R^(3) rho))` `T^(2) = 4pi^(2)(3)/(G xx 4 pi rho)` `T^(2) = (3pi)/(G rho)` |
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