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The average energy flux of sunlight is `1.0 kW m^-2`. This energy of radiation is falling normally on the metal plate surface of area `10 cm^2` which completely abosbs the energy. How much force is exerted on the plate if it is exposed to sunlight for 10 minutes? |
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Answer» Correct Answer - `3.3xx10^-9N` Here, energy flux,`=1.0kWm^-2` `=1.0xx10^3Wm^-2`, `A=10cm^2=10xx10^-4m^2=10^-3m^2` `t=10min=10xx60s=600s`. Total energy falling on the plate. U=energy flux x area x time `=(1xx10^3)xx(10^-3)xx(600)J=600J` Momentum of the radiation `p=U/c=600/(3xx10^8)=2xx10^-6kgms^-1` Since the plate absorbs the entire energy, so momentum delivered to the plate= change in momentum `(Deltap)=2xx10^-6kgms^-1` Force on the plate, `F=(Deltap)/t=(2xx10^-6)/60=3.3xx10^-9N` |
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