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The average K.E. of an ideal gas in calories per mole is approximately equal to * 1 pointA) Three times the absolute temperatureB) absolute temperatureC) two times the absoluteD) 1.5 times the absolute temperature |
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Answer» AExplanation:K.E =3/2.RT=3/2.2T sinceR~=2calK- HOPE it may help U MARK it as BRAINLIST |
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