1.

The average of five positive numbers is 319.20. The average of first two numbers is 482.5 and the average of last two numbers is 258.5. What is the number after interchanging hundredth place digit and unit place digit of the third number?1). 1142). 4113). 1414). Cannot be determined

Answer»

Let five positive numbers be a, b, c, d and e

The average of five positive numbers is 319.20

⇒ ( a + b + c + d + e )/5 = 319.2

⇒ a + b + c + d + e = 319.2 × 5 = 1596. . . . equation (1)

The average of first TWO numbers is 482.5

⇒ (a + b)/2 = 482.5

⇒ a + b = 482.5 × 2

⇒ a + b = 965. . . . equation (2)

The average of last two numbers is 258.5

⇒ (d + e)/2 = 258.5

⇒ d + e = 258.5 × 2 = 517. . . . equation (3)

Using equations (2) and (3) in equation (1), we get

⇒ 965 + c + 517 = 1596

⇒ c = 1596 – (965 + 517) = 1596 – 1482 = 114

The number after interchanging hundredth place digit and unit place digit of the THIRD number = 411


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