The average of n numbers is 42. If 60% of the numbers are increased by

1.	The average of n numbers is 42. If 60% of the numbers are increased by 5 each and the remaining numbers are decreased by 10 each. then what will be the average of the numbers so obtained?1. 412. 453. 434. 42
Answer» Correct Answer - Option 1 : 41 Given: The average of n numbers is 42. If 60% of the numbers are increased by 5 each and the remaining numbers are decreased by 10 each. Concept used: Average Calculation: Let the N number be 100 and their average is 42. The average increases by 5 for 60% of numbers New average : 42 + 5 = 47 Sum = 60% of 100 × 47 Sum = 60 × 47 = 2820 For the remaining 40% average decreases by 10 each. New average : 42 - 10 = 32 Sum = 40% of 100 × 32 Sum = 40 × 32 = 1280 Average = \(\frac{{2820\ +\ 1280}}{{100}}\) Average = 41

The average of n numbers is 42. If 60% of the numbers are increased by 5 each and the remaining numbers are decreased by 10 each. then what will be the average of the numbers so obtained?1. 412. 453. 434. 42

Answer» Correct Answer - Option 1 : 41

Given:

The average of n numbers is 42. If 60% of the numbers are increased by 5 each and the remaining numbers are decreased by 10 each.

Concept used:

Average

Calculation:

Let the N number be 100 and their average is 42.

The average increases by 5 for 60% of numbers

New average : 42 + 5 = 47

Sum = 60% of 100 × 47

Sum = 60 × 47 = 2820

For the remaining 40% average decreases by 10 each.

New average : 42 - 10 = 32

Sum = 40% of 100 × 32

Sum = 40 × 32 = 1280

Average = \(\frac{{2820\ +\ 1280}}{{100}}\)

Average = 41

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