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The average rotational kinetic energy of hydrogen molecule at a temperature `T` is `E`. The average translational kinetic energy of helium at same temperature will be:A. `(2E)/(3)`B. `(5E)/(3)`C. `E`D. `(3E)/(2)` |
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Answer» Correct Answer - D Law of equipartition of energy `lt KE_(R)gt = 2.(1)/(2)kT = E` `:. ltKE_(T)gt = 3. (1)/(2)kT` `ltKE_(T)gt = (3E)/(2)` |
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