1.

The average rotational kinetic energy of hydrogen molecule at a temperature `T` is `E`. The average translational kinetic energy of helium at same temperature will be:A. `(2E)/(3)`B. `(5E)/(3)`C. `E`D. `(3E)/(2)`

Answer» Correct Answer - D
Law of equipartition of energy
`lt KE_(R)gt = 2.(1)/(2)kT = E`
`:. ltKE_(T)gt = 3. (1)/(2)kT`
`ltKE_(T)gt = (3E)/(2)`


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