InterviewSolution
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InterviewSolution
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The average speed of gas molecules is equal toA. `((8 RT)/(pi M))^(1//2)`B. `((3 RT)/( M))^(1//2)`C. `((2 RT)/( M))^(1//2)`D. `(( RT)/( M))^(1//2)` |
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Answer» Correct Answer - A If there are `n` number of molecules in a sample and their individual speeds are `u_(1),u_(2),….u_(n)`, then the average speed of molecules `u_(av)` can be calculated as follows: `u_(av) = (u_(1) + u_(2) + … + u_(n))/(n)` According to the Maxwell-Boltzmann distribution of speeds, it is given as `u_(av) = sqrt((8 RT)/(pi M))` Option (2) is root mean square speed and option (3) is most probable speed. |
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