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The average value of rotational kinetic energy of one mole of oxygen gas at temperature T will be (A) RT (B) 3/2 RT(C) 5/2 RT(D) 1/2 RT |
Answer» Correct option (A) RT Explanation: The degree of freedom of 1 mole of O2 gas is 5. Out of which 3 are translational and 2 are rotational. Now, the average kinetic energy is given as F/2 RT where f is degree of freedom for rotational motion. Therefore, the average kinetic energy is RT . |
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