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CH3MgI will give methane with (A) C2H5OH (B) CH3–CH2–NH2(C) both of these (A and B) (D) None of these |
Answer» Correct option (C) both of these (A and B) Explanation: Grignard’s reagent reacts with primary or secondary amines to give alkanes but fail to react with tertiary amines due to lack of hydrogen on nitrogen. R-MgX + R-NH₂ → R-H + Mg(NHR) The reaction between ethanol and Grignard is shown below: CH3CH2OH + R’MgX → CH3CH2O-(MgX)+ + R’-H |
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