The average velocity of nitrogen at 27^@C is 0.3ms^(-1). At what temperature it will be 0.6 ms^(-1)?

The average velocity of nitrogen at 27^@C is 0.3ms^(-1). At what tempe

1.	The average velocity of nitrogen at 27^@C is 0.3ms^(-1). At what temperature it will be 0.6 ms^(-1)?
Answer» Solution :Average VELOCITY is given as `bar(C) = sqrt((8RT)/(PI M))` The RATIO of velocities at two different temperatures for the same GAS is given as`(bar(C_1))/(bar(C_2)) = sqrt((T_1)/(T_2))` Substituting the values, the ratio is `= (0.3)/(0.6) = sqrt((300)/(T_2)) = 1/2` The TEMPERATURE, `T_2 = 2^2 xx 300 = 1200 K = 927^@C`.