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The average veloctiy of an ideal gas molecule at `27^(@)C` is `0.3 m s^(-1)`. The average velocity at `927^(@)C` will beA. `0.6 m s^(-1)`B. `0.3 m s^(-1)`C. `0.9 m s^(-1)`D. `3.0 m s^(-1)` |
Answer» `(v_(1))/(v_(2))=sqrt((T_(1))/(T_(2)))` `T_(1)=273^(@)C=300K` `T_(2)=927^(@)C=1200K` `V_(1)=0.3 m s^(-1)` `V_(2)=sqrt((T_(2))/(T_(1))xxV_(1)=sqrt(1200)/(300)xx0.3=0.6m s^(-1)` |
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