1.

The average weight of 10 employees is 45 kg which is equal to two times of the average weight of 5 servants. Quantity I: What is the average weight of the 10 employees and 5 servants?Quantity II: 45 kg 1. Quantity 1 > Quantity 22. Quantity 1 ≥ Quantity 23. Quantity 1 < Quantity 24. Quantity 1 ≤ Quantity 25. Quantity 1 = Quantity 2

Answer» Correct Answer - Option 3 : Quantity 1 < Quantity 2

Given:

Avg weight of 10 employees = 45 kg = 2 × avg weight of 5 servants

Calculation:

Weight of 10 employees = 45 × 10

⇒ Weight of 10 employees = 450 kg

Weight of 5 servants = 45 × 5 / 2

⇒ Weight of 5 servants = 112.5 kg

⇒ The sum of the weight of 10 employees and 5 servants = 450 + 112.5

⇒ 562.5 kg

Quantity I:

Required average = 562.5 / 15 ≈ 37.5 kg

Quantity II: 45 kg

∴ Quantity I < Quantity II



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