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The average weight of 10 men is increased by \(1\frac{1}{2}\) kg when one of the men whose weight is 68 kg, is replaced by a new man. Find the weight of the new man.1). 87 kg2). 59 kg3). 85 kg4). None of these |
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Answer» SINCE the average has increased, the new MAN will have weight more than 68. Let, the original average be a, and let the weight of new man be x. Average = Total weight / No. of people ∴a = (Total weight of 9 people + 68)/10 ⇒ 10a = 68 + Total weight of 9 people (Weight of remaining 9 people remains unchanged) New average will be (1.5 + a) = (Total weight of 9 people + x)/10 ⇒1.5 + a = [(10a – 68) + x]/10 ⇒ 15 + 10a = 10a – 68 + x ⇒ x = 15 + 68 = 83 KG |
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