The balanced equation for a reaction is given below 2x + 3y rarr 41 +m When 8 moles of x react with 15 moles of y, then Which is the limiting reagent ? (b) Calculate the amount of products formed. Calculate the amount of excess reactant left at the end of the reaction.

The balanced equation for a reaction is given below 2x + 3y rarr 41 +m

1.	The balanced equation for a reaction is given below 2x + 3y rarr 41 +m When 8 moles of x react with 15 moles of y, then Which is the limiting reagent ? (b) Calculate the amount of products formed. Calculate the amount of excess reactant left at the end of the reaction.
Answer» Solution :2X + y `RARR` 41 + m (i) 2x reacts with 3y to give products. 8x reacts with 15Y means, y is the excess because 8 moles of x should react with `4 xx 3y = 12y` moles of y to give products. Therefore, 3 moles of y is excess and x is the limiting agent. When 8 moles of x react with 12 moles of y, the product formed will be `4 xx 4l` i.e. 161 and 4m as product. `8x + 2y rarr 161 + 4m` At the end of the REACTION, the excess reactant left is 3 moles of y.