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The balanced equation for a reaction is given below 2x + 3y → 41 + m When 8 moles of x react with 15 moles of y, then – 1. Which is the limiting reagent? 2. Calculate the amount of products formed. 3. Calculate the amount of excess reactant left at the end of the reaction. |
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Answer» 2 x + 3 y → 41 + m 1. 2x reacts with 3y to give products. 5x reacts with l5y means, y is the excess because 8 moles of x should react withn 4 x 3y = 12y moles of y to give products. In this reaction 15y moles are used. Therefore, 3 moles of y is excess and it is the limiting agent. 2. When 8 moles of x react with 12 moles of y, the product formed will be 4 x 41 i.e. 161 and 4m as product. 8x + 12y → 161 + 4m 3. At the end of the reaction, the excess reactant left in 3 moles of y. |
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