1.

The base edge of a square pyramid is Stem, height 3cm. Calculate slant height and lateral edge

Answer»

Base edge = 8 cm, height = 3 cm

Slant height = \(\sqrt{(\frac{8}{2})^2+(3)^2}\) = \(\sqrt{16+9}\) = \(\sqrt{25}\) = 5

Length of lateral edge = \(\sqrt{(slant\,height)^2+(\frac{base\,edge}{2})^2}\)

\(\sqrt{(5)^2+4^2}{}\)

\(\sqrt{25+16}\)

\(\sqrt{41}\) cm



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