The base imidazole has a `K_(b)` of `8.1 xx 10^(-8)`. a. In what amounts should `0.02 M HCI` and `0.02M` imidazole be mixted to make `100mL` of a buffer at `pH 7`? b. If the resulting solution is diluted to `1L`, what is the `pH` of the diluted solution?

The base imidazole has a `K_(b)` of `8.1 xx 10^(-8)`. a. In what amoun

1.	The base imidazole has a `K_(b)` of `8.1 xx 10^(-8)`. a. In what amounts should `0.02 M HCI` and `0.02M` imidazole be mixted to make `100mL` of a buffer at `pH 7`? b. If the resulting solution is diluted to `1L`, what is the `pH` of the diluted solution?
Answer» a. `pOH = pK_(b) +log ("salt/base")` `7 = 8 - 0.90848 + log ("salt/base")` and `("base/salt") = 1.234458`. Let `xmL` of `HCI` and `ymL` of imisazole are mixed (since molarity is same) `{:(,,HCI+,Baserarr,"Salt"),("Initial",,x,(y),0),("Final",,0,(y-x),x):}` `x +y = 100mL, y = 100 - x` `("Base")/("Salt") = (y-x)/(x) = (100-2x)/(x) = 1.2358` `x = 30.9 mL ("volume of acid")` Volume of imidanzole `= 100 - 30.9 = 69.1` b. `pH remains same (since on dilution the concentration of salt and base changes in the same proportions).

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The base imidazole has a `K_(b)` of `8.1 xx 10^(-8)`. a. In what amounts should `0.02 M HCI` and `0.02M` imidazole be mixted to make `100mL` of a buffer at `pH 7`? b. If the resulting solution is diluted to `1L`, what is the `pH` of the diluted solution?

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