The base of a triangular field is three times its altitude. If the cos

1.	The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and height.
Answer» Area of the field = Total cost/rate = (333.18/25.6)hectares = 13.5 hectares (13.5 x 10000) m² = 135000 m² . Let altitude = x metres and base = 3x metres. Then, (1/2)* 3x * x = 135000 <=>x² = 90000 <=>x = 300. Base = 900 m and Altitude = 300 m.

The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and height.

Answer»

Area of the field = Total cost/rate = (333.18/25.6)hectares = 13.5 hectares

(13.5 x 10000) m² = 135000 m² .

Let altitude = x metres and base = 3x metres.

Then, (1/2)* 3x * x = 135000 <=>x² = 90000 <=>x = 300.

Base = 900 m and Altitude = 300 m.