1.

The base of an isoceles triangle measure 24 cm and its area is 60cm² find its perimeter

Answer» Altitude in an isosceles triangle is = h{tex}Area = \\frac{1}{2}\\ h\\ a\\ =\\ 60\\ cm^2 \\\\ \\\\ h\\ =\\ 2\\ *\\ \\frac{60}{24} = 5 cm \\\\ \\\\ b^2 = \\frac{a}{2}^2 + h^2 = 12^2 + 5^2 = 169 \\\\ \\\\ b = c = 13 cm \\\\ \\\\ Perimeter = a+b+c = 24+13+13 = 50 cm{/tex}\xa0\xa0


Discussion

No Comment Found