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The base of an isosceles triangle is `4/3 cm.` The perimeter of the triangle is `(4) 2/(15) cm.` What is the length of either of the remaining equal sides? |
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Answer» Let any of the remaining side of the isosceles triangle is `x` cm in length. Then, Perimeter of triangle, ` = x+x+4/3 = 2x+4/3` cm `=>2x+4/3 = 4 2/15`( Perimeter is `4 2/15`) `=>2x+4/3 = 62/15=>2x = 62/15-4/3` `=> 2x = 42/15 => x = 14/10 = 7/5 = 1 2/5` cm So, Required sides of given triangles are `1 2/5` cm each. |
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