1.

The base radius of an iron cylinder is 15 centimetres and its height is 32 centimetres. It is melted and re-cast into a cylinder of base radius 20 centimetres. What is the height of this cylinder?

Answer»

Volume of the first cylinder

= π R2 H = π (15)2 x 32 = 7200 π

Volume of the melted and recast cylinder = π r2h = π (20)2 x h = 400 π h

Volume remains constant when melted.

400 π h = 7200π

h = \(\frac{7200\pi}{400\pi}\) = 18

Height of the second cylinder = 18 cm



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