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The base radius of an iron cylinder is 15 centimetres and its height is 32 centimetres. It is melted and re-cast into a cylinder of base radius 20 centimetres. What is the height of this cylinder? |
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Answer» Volume of the first cylinder = π R2 H = π (15)2 x 32 = 7200 π Volume of the melted and recast cylinder = π r2h = π (20)2 x h = 400 π h Volume remains constant when melted. 400 π h = 7200π h = \(\frac{7200\pi}{400\pi}\) = 18 Height of the second cylinder = 18 cm |
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