The binding energies per nucleon for a deuteron and an α-particles are X1 and X2 respectively, then the free energy Q released in the fusion reaction, \(_{1}^{2} {H}+_{1}^{2} {H} \longrightarrow_{2}^{4} {He}+Q\), is :(a) 4 (X1 + X2)(b) 4 (X1 – X2)(c) 2 (X1 + X2)(d) 2 (X2 – X1)

The binding energies per nucleon for a deuteron and an α-particles ar

1.	The binding energies per nucleon for a deuteron and an α-particles are X1 and X2 respectively, then the free energy Q released in the fusion reaction, \(_{1}^{2} {H}+_{1}^{2} {H} \longrightarrow_{2}^{4} {He}+Q\), is :(a) 4 (X1 + X2)(b) 4 (X1 – X2)(c) 2 (X1 + X2)(d) 2 (X2 – X1)
Answer» (b) 4(X₁ – X₁) ₁H² + ₁H² → ₂Hi⁴ + Q Q = 2X₁ + 2X₁ – 4X₂ Q = 4X₁ – 4X₂ Q = 4(X₁ – X₂)

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The binding energies per nucleon for a deuteron and an α-particles are X1 and X2 respectively, then the free energy Q released in the fusion reaction, \(_{1}^{2} {H}+_{1}^{2} {H} \longrightarrow_{2}^{4} {He}+Q\), is :(a) 4 (X1 + X2)(b) 4 (X1 – X2)(c) 2 (X1 + X2)(d) 2 (X2 – X1)

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