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The binding energy of 21Sc45 is 368 MeV. What is its atomic mass? Given that : Mass of 1H1 = 1.008143 u Mass of neutron = 1.008986u. |
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Answer» The 21Sc45 atom has 21 protons and 24 neutrons in its nucleus. Mass of 21 protons = 21 × 1.008143 = 21.171003u Mass of 24 neutrons = 24 × 1.008986 = 24.215664u Total mass = 21.171003 + 24.215664 = 45.386667u Mass defect = \(\frac{368}{931}\) = 0.395274u ∴Atomic mass of 21Sc45 = 45.386667 – 0.395274 = 44.991393u |
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