1.

The binding energy of 21Sc45 is 368 MeV. What is its atomic mass? Given that : Mass of 1H1 = 1.008143 u Mass of neutron = 1.008986u.

Answer»

The 21Sc45 atom has 21 protons and 24 neutrons in its nucleus. 

Mass of 21 protons = 21 × 1.008143 

= 21.171003u 

Mass of 24 neutrons = 24 × 1.008986 

= 24.215664u 

Total mass = 21.171003 + 24.215664 

= 45.386667u 

Mass defect = \(\frac{368}{931}\)

= 0.395274u 

∴Atomic mass of 21Sc45 = 45.386667 – 0.395274 

= 44.991393u



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