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The binding energy per nucleon of `._(5)B^(10)` is 8 MeV and that of `._(5)B^(11)` is 7.5 MeV. The energy required to remove a neutron from `._(5)B^(11)` is (mass of electron and proton are `9.11 xx 10^(-21) kg` and `1.67 xx 10^(-27) kg` respectively.A. `2.5 MeV`B. `8.0 MeV`C. `0.5 MeV`D. `7.5 MeV` |
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Answer» Correct Answer - A `10 xx 8 = 80` `11 xx 7.5 = 82.5` Energy required `= 82.5 -80 = 2.5` |
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