1.

The bob A of a pendulum of length 1 m released from 30^(@) to the vertical hits another bob B of same mass at rest on the table. How high does the bob A rise after the collision and find the velocity of B.

Answer»

Solution :The BOB of pendulum acquires a velocity
`V = sqrt(2gl(1-costheta))`,
onreaching the LOWER most POSITION and makes elastic collision with the bob B of same mass.

Hence the bodies simply exchange their velocities after collision. The bob of pendulum does not RISE at all and velocity of B is `V=sqrt(2gl(1-costheta))=1.62ms^(-1)`


Discussion

No Comment Found