The bob A of a pendulum of length 1m released from 30^(@) to the vertical hits another bob B of same mass at rest on the table. How high does the bob A rise after the collision and find the velocity of B.

The bob A of a pendulum of length 1m released from 30^(@) to the verti

1.	The bob A of a pendulum of length 1m released from 30^(@) to the vertical hits another bob B of same mass at rest on the table. How high does the bob A rise after the collision and find the velocity of B.
Answer» Solution :The bob of pendulum acquires a velocity `V= sqrt(2gl(1- cos THETA))`, on REACHING the lower most POSITION and makes elastic collision with the bob B of same mass. Hence the bodies simply EXCHANGE their velocities after collision. The bob of pendulum does not RISE at all and velocity of B is `V= sqrt(2gl(1- cos theta))= 1.62 ms^(-1)`