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The bob A of pendulum of length 1 m released from 30^(@) to the vertical hits another bob B of same mass at rest on the table. How high does the bob A rise after the collision and find the velocity of B. |
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Answer» Solution :The bob of pendulum acquires a VELOCITY `V=SQRT(2gl(1-cos theta))`, on reaching the LOWER most position and makes elastic collision with the bob B of same mass. ![]() Hence the bodies simply EXCHANGE their velocities after collision. The bob of pendulum does not rise at all and velocity of B is `V = sqrt(2gl(1-cos theta))=1.62 ms^(-1)` |
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