1.

The bob A of pendulum of length 1 m released from 30^(@) to the vertical hits another bob B of same mass at rest on the table. How high does the bob A rise after the collision and find the velocity of B.

Answer»

Solution :The bob of pendulum acquires a VELOCITY
`V=SQRT(2gl(1-cos theta))`,
on reaching the LOWER most position and makes elastic collision with the bob B of same mass.

Hence the bodies simply EXCHANGE their velocities after collision. The bob of pendulum does not rise at all and velocity of B is
`V = sqrt(2gl(1-cos theta))=1.62 ms^(-1)`


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