The bob of pendulum is released from a horizontal position . If the length of the pendulum is 1.5 m,what is the speed with which the bob arrives at the speed with whichthe bob arrivesat the lowermost point , given that it dissipated 5 % of its intial energy against air resistance ?

The bob of pendulum is released from a horizontal position . If the le

1.	The bob of pendulum is released from a horizontal position . If the length of the pendulum is 1.5 m,what is the speed with which the bob arrives at the speed with whichthe bob arrivesat the lowermost point , given that it dissipated 5 % of its intial energy against air resistance ?
Answer» Solution : KINETIC ENERGY at point B = 95 % POTENTIAL energy at point A , `1/2 MV^(2) = 0.95 xx mgh` ` :. 1/2 mv^(2) = 0.95 xx mgh` ` :. V^(2) = 2XX 0.95 xxgh` ` :. v = sqrt(2xx0.95 xx9.8 xx1.5) = 5.285 ms^(-1)= 5.3 ms^(-1)`