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The bobof mass50 gm of a pendulumis released from a horizontal position A as shownin the figure ..If the lengthof the pendulumis1.5 m , what is itskinetic energyat the lowermostpointB ? (g = 10 m/(s^(2))) |
Answer» <html><body><p>`2.5 xx10^(-11)` J <br/>`15 xx10^(-1) J ` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/5xx10-1901302" style="font-weight:bold;" target="_blank" title="Click to know more about 5XX10">5XX10</a>^(-1) J ` <br/>`7.5 xx10^(-1) J ` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Potential energy of a bob of pendulum at pointA = K.E of bob at <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> B <br/>` :. ` K.E of bob at `B(1/2 <a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>^(2)) = <a href="https://interviewquestions.tuteehub.com/tag/mgh-1095458" style="font-weight:bold;" target="_blank" title="Click to know more about MGH">MGH</a> ` <br/> ` = 50 xx10^(-3) xx10 xx1/5` <br/> `= 7.5 xx10^(-1) J `</body></html> | |