1.

The bobof mass50 gm of a pendulumis released from a horizontal position A as shownin the figure ..If the lengthof the pendulumis1.5 m , what is itskinetic energyat the lowermostpointB ? (g = 10 m/(s^(2)))

Answer»

`2.5 xx10^(-11)` J
`15 xx10^(-1) J `
`5XX10^(-1) J `
`7.5 xx10^(-1) J `

SOLUTION :Potential energy of a bob of pendulum at pointA = K.E of bob at POINT B
` :. ` K.E of bob at `B(1/2 MV^(2)) = MGH `
` = 50 xx10^(-3) xx10 xx1/5`
`= 7.5 xx10^(-1) J `


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