The Bohr's radius of Li^(2+) of 2^(nd) orbit is………….

1.	The Bohr's radius of Li^(2+) of 2^(nd) orbit is………….
Answer» Solution :0.7053A `r_n=((0.529xx2^(3)n^(2)))/(Z)A,n=2,Z=3(For Li^(2+))` `R=(0.259xx2^(2)=(0.529xx4)/(3))=0.7053A`

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