1.

The boiling point of a 0.2 m solution of a non-electrolyte in water is : (Kb for water = 0.52 K kg mol-1)(A) 100°C(B) 100.52°C(C) 100.104°C(D) 100.26°C

Answer»

Option : (C) 100.104°C

We know that,

ΔTb = Kbm

m = molality.

ΔTb = 0.52 kg mol-1 x 0.2 mol/kg

ΔTb = 0.104 K

It means -

Boiling point increases by 0.104 K or 0.104°C

Hence,

The boiling point of 0.2 m solution of a non-electrolyte in water will be 100.104°C



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