1.

The boiling point of a solution of 0.11 gm of a substance in 15 gm of ether was found to be `0.1^(@)C` higher than that of the pure ether. The molecular weight of the substance will be `(K_(b)=2.16)`A. 148B. 158C. 168D. 178

Answer» Correct Answer - B
`m=(K_(b)xx w xx1000)/(Delta T_(b)xx W)`
`K_(b)=2.16, w=0.11, W=15 g, Delta T_(b) =0.1`
`m=(2.16xx0.11xx1000)/(0.1xx15)=158.40 ~= 158`.


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