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The boiling point of an aqueous solution of a non-volatile solute is `100.15^(@)C`. What is the freezing point of an aqueous solution obtained by dilute the above solution with an equal volume of water. The values of `K_(b)` and `K_(f)` for water are `0.512` and `1.86^(@)C mol^(-1)`:A. `-0.544^(@)C`B. `-0.512^(@)C`C. `-0.272 ^(@)C`D. `-1.86 ^(@)C` |
Answer» Correct Answer - C For same solution `(Delta T_(f))/(Delta T_(b))=K_(f)/K_(b) ` or `Delta T_(f) = Delta T_(b) xx K_(f)/K_(b)` or `Delta T_(f) = (0.15 xx 1.86)/20.512=0.545` Now on diluting the solution to double ` :. Delta T_(f) = 0.545/2=0.272` `:. f. pt. = -0.272^(@) C` |
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